EjerciciosFyQ

Relationship between molarity and normality (8380)

F_y_Q — 2025-01-27T04:52:56Z

Calculate the normality of the following solutions: a) (2 M) b) (0.4 M) c) (3 M) d) (1 M) e) (2 M)

Normality is defined as the number of equivalents of solute in one liter of solution. The mass of an equivalent is the molecular mass divided by the number of "H" or "OH" groups in the acid or base considered. This means that the relationship between normality and molarity is that normality is equal to molarity multiplied by the number of "H" or "OH" groups in the species.

a)

b)

c)

d)

e) (because it is a salt with a 1:1 stoichiometry between its ions).

Molarity from % (m/V) concentration (8303)

F_y_Q — 2024-09-08T03:42:27Z

Calculate the molarity of a sulfurous acid solution whose concentration is (m/V).

First, set a quantity of solution as the basis for calculation. Consider 100 mL of solution, which gives you 8 g of solute, , (these amounts are the “translation” of m/V).

The moles corresponding to that mass of solute are obtained from the molecular mass of the acid:

Calculate the moles equivalent to the mass of solute:

The molarity is the ratio between the moles of solute and the volume of the solution, expressed in liters, i.e., 0.1 L (because you considered 100 mL at the beginning):