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		<title>Lengthening of a spring when a force is applied (4843)</title>
		<link>https://www.ejercicios-fyq.com/Lengthening-of-a-spring-when-a-force-is-applied-4843</link>
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		<dc:date>2019-11-11T18:42:07Z</dc:date>
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		<dc:language>es</dc:language>
		<dc:creator>F_y_Q</dc:creator>


		<dc:subject>EDICO</dc:subject>
		<dc:subject>Hooke's law</dc:subject>
		<dc:subject>SOLVED</dc:subject>

		<description>
&lt;p&gt;A spring has an elastic constant of 120 N/m. Calculate how much it will lengthen if a force of 35 N is applied.&lt;/p&gt;


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 <content:encoded>&lt;div class='rss_texte'&gt;&lt;p&gt;A spring has an elastic constant of 120 N/m. Calculate how much it will lengthen if a force of 35 N is applied.&lt;/p&gt;&lt;/div&gt;
		&lt;hr /&gt;
		&lt;div &lt;div class='rss_ps'&gt;&lt;p&gt;Use the Hooke's law to solve the problem: &lt;br/&gt; &lt;br/&gt; &lt;p class=&#034;spip&#034; style=&#034;text-align: center;&#034;&gt;&lt;img src='https://www.ejercicios-fyq.com/local/cache-TeX/ed8208e3cb3d08eebc0f94a4fe04ef30.png' style=&#034;vertical-align:middle;&#034; width=&#034;430&#034; height=&#034;57&#034; alt=&#034;F = k\cdot \Delta x\ \to\ \Delta x = \frac{F}{k} = \frac{35\ \cancel{N}}{120\ \frac{\cancel{N}}{m}}= \fbox{\color[RGB]{192,0,0}{\bf 0.29\ m}}&#034; title=&#034;F = k\cdot \Delta x\ \to\ \Delta x = \frac{F}{k} = \frac{35\ \cancel{N}}{120\ \frac{\cancel{N}}{m}}= \fbox{\color[RGB]{192,0,0}{\bf 0.29\ m}}&#034; /&gt;&lt;/p&gt;
&lt;/math&gt;&lt;/p&gt;
&lt;p&gt; &lt;br/&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;&lt;a href=&#034;https://ejercicios-fyq.com/Situaciones-de-aprendizaje/EDICO/Ej_4843.edi&#034; download&gt;Download the statement and the solution of the problem in EDICO format if you need it.&lt;/a&gt;&lt;/b&gt;&lt;/p&gt;&lt;/div&gt;
		
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